-1=5/(x^2-1)

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Solution for -1=5/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

-1 = 5/(x^2-1) // - 5/(x^2-1)

-(5/(x^2-1))-1 = 0

-5*(x^2-1)^-1-1 = 0

-5/(x^2-1)-1 = 0

(-1*(x^2-1))/(x^2-1)-5/(x^2-1) = 0

-1*(x^2-1)-5 = 0

-x^2-4 = 0

(-x^2-4)/(x^2-1) = 0

(-x^2-4)/(x^2-1) = 0 // * x^2-1

-x^2-4 = 0

-1*x^2 = 4 // : -1

x^2 = -4

x belongs to the empty set

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